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7x^2-68x+160=0
a = 7; b = -68; c = +160;
Δ = b2-4ac
Δ = -682-4·7·160
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-12}{2*7}=\frac{56}{14} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+12}{2*7}=\frac{80}{14} =5+5/7 $
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